Respuesta :

Wolfblack

Answer:

[tex]\sqrt{18} + \sqrt{32} - 3 \sqrt{8} = \\ = \sqrt{9 \times 2} + \sqrt{16 \times 2} - 3 \sqrt{4 \times 2} \\ =3 \sqrt{2} + 4 \sqrt{2} - 3 \times 2 \sqrt{2} \\ = 3 + 4 - 6 \sqrt{2} \\ = 7 - 6 \sqrt{2} \\ = 1 \sqrt{2} [/tex]

Semoga membantu

Answer:

[tex]\sqrt{18} + \sqrt{32} - 3 \sqrt{8} = 1 \sqrt{2} [/tex]