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A circus performer walks a tightrope 315 m above the ground. Suppose a coin falls from his pocket during his walk. How much potential energy does the coin (m = 0.015 kg) have when its speed is 60.0m/s?

Respuesta :

okpalawalter8

The potential energy of the coin is mathematically given as

P.E=26.99949J

Potential energy of coin

Question Parameters:

A circus performer walks a tightrope 315 m above the ground.

(m = 0.015 kg) have when its speed is 60.0m/s

Generally the equation for the Newtons equation  is mathematically given as

v 2 - u 2 =2aS  

Therefore

S = [ v 2 - u2 ] / 2a

S = [ 60-0 ] / 2*9.8

S= 183.67 m

Therefore,P.E

P.E=mgh

hence

P.E=0.015*9.8*183.67

P.E=26.99949J

For more information on Speed

https://brainly.com/question/4931057

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