Answer:
2325 mL
Step-by-step explanation:
Let x = total volume of the tank. When we fill 4/5 of water into the tank, the amount of water we have can be expressed by 4x/5. Then we only keep 1/3 of that amount (poured away 2/3 of the water), so the amount of water is 4x/15. Thus we set up the equation like this:
4x/15 = 620
4x = 9300
x = 2325
Thus the tank can contain a maximum of 2325 mL.
