given:
N2(g) + 3H2(g) → 2NH3(g)
20ml of nitrogen
to find:
the volume of produced NH3
solution:
So, 1 volume of nitrogen gas reacts with 3 volumes of hydrogen gas to produce 2 volumes of ammonia gas.
For this gaseous reaction in which all the reactants and products are gases we could write a chemical equation:
1 volume N2(g) + 3 volumes H2(g) → 2 volumes NH3(g)
1 volume of N2 is 20 ml so 2 volume of NH3 will be 40 ml .
Then , 20 ml N2 will give 40 ml of NH3
= 40 ml
