You have the expression:
[tex]\frac{6a^3+(4b-c)^2}{2}[/tex]
And the given values are:
a=5
b=3
c=2
You substitute the given values in the equation:
[tex]\frac{6(5^3)+(4(3)-2)^2}{2}[/tex]
Then you make the opperations:
[tex]\frac{6(125)+(12-2)^2}{2}[/tex][tex]\frac{750+10^2}{2}[/tex][tex]\frac{750+100}{2}[/tex][tex]\frac{850}{2}[/tex]Finally, you get:[tex]\frac{850}{2}=425[/tex]
