Answer:
[tex]f(x)=e^x[/tex]
Explanation:
First, the function, g(x):
[tex]g(x)=e^{\cos(x)}[/tex]
The function g(x) oscillates, thus, it does not increase.
The value of 'e' is approximately 2.7.
[tex]\begin{gathered} f(x)=e^x\approx2.7^x \\ h(x)=(2.5)^x \end{gathered}[/tex]
Since 2.7 is greater than 2.5, we can infer that f(x) grows the fastest as x grows without bound.
