c)
We know that:
[tex](f\circ g)(x)=2x+4[/tex]
to find the function at x=1 we just plug this value of x in the expression found:
[tex](f\circ g)(1)=2(1)+4=2+4=6[/tex]
Therefore:
[tex](f\circ g)(1)=6[/tex]
d)
We know that:
[tex](g\circ f)(x)=2x+7[/tex]
Then we have:
[tex](g\circ f)(1)=2(1)+7=2+7=9[/tex]
Therefore:
[tex](g\circ f)(1)=9[/tex]
