Respuesta :

x^0 y^-3 / x^2 y^-1 
= 1 /  x^2 y^-1 (y^3)  ...because  x^0 = 1 and  [(y^-1) (y^3)] = y^2
= 1/(x^2 y^2)
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But if you're adding them the answer would be [tex]1/ x^{2}y^2 [/tex]

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