d/dx[tex] \int\limits^0_x {cos(2 \pi u)} \, du[/tex] is

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26-03-2017
Mathematics

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d/dx[tex] \int\limits^0_x {cos(2 \pi u)} \, du[/tex] is

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LammettHash LammettHash · Answer 1 · 2017-03-28T00:20:21+02:00

LammettHash LammettHash

28-03-2017

[tex]\displaystyle\frac{\mathrm d}{\mathrm dx}\int_x^0\cos2\pi u\,\mathrm du=-\frac{\mathrm d}{\mathrm dx}\int_0^x\cos2\pi u\,\mathrm du=-\cos2\pi x[/tex]

by the fundamental theorem of calculus.

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