x-y=5 xy=3.36 add y to both sides on first x=5+y sub that in other eqation (5+y)y=3.36 expand y^2+5y=3.36 minus 3.36 both sides y^2+5y-3.36=0 use quadratic formula
for ay^2+by+c=0 [tex]y= \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/tex] for 1y^2+5y-3.36 [tex]y= \frac{-5+/- \sqrt{5^2-4(1)(-3.36)} }{2(1)} [/tex] [tex]y= \frac{-5+/- \sqrt{25+13.44} }{2} [/tex] [tex]y= \frac{-5+/- \sqrt{38.44} }{2} [/tex] [tex]y= \frac{-5+/- 6.2}{2} [/tex] y=-2.5+/-3.1 y=5.6 or 0.6 sub back
x=y+5 so x=10.6 or 5.6
the numbers are either 10.6 and 5.6 or 0.6 and 5.6 wait,but 10.6 and 5.6 don't multiply to get 3.36 so that is an extrainiesous answer
