sofiabecerra17 sofiabecerra17

21-06-2017
Mathematics

contestada

In geometric sequence the 4th term is 54 the 7th term is 1458 what is the 12th term

Respuesta :

mathmate mathmate

24-06-2017

Let the common ratio be r.
a4=54
a7=1458
r^3=1458/54=27
r=27^(1/3)=3
therefore
a12=a7*r(12-7)=a7*3^5
=354294

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