Respuesta :

mreijepatmat
Sample space = {52 cards} = all possible outcomes
favorable outcome = 26 RED card

P(1st RED card) = 26/52 = 1/2 = 0.5
P(2ndt RED card) = 25/51 = 1/2 = 0.49 (since their is no replacement)
P(3rd RED card) = 24/50 = 1/2 = 0.48

Now P(1st RED AND 2nd RED and 3rd READ) = 0.5 x 0.49 x 0.48 =0.1152

P(1st RED ∩ 2nd RED ∩ 3rd READ) = 0.115