What are the real zeros of x^3 + 4x^2 − 9x − 36

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25-07-2017
Mathematics

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What are the real zeros of x^3 + 4x^2 − 9x − 36

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nicolson123 nicolson123 · Answer 1 · 2017-07-25T17:06:13+02:00

nicolson123 nicolson123

25-07-2017

x3 + 4x2 -9x -36
[x3 + 4x2] -9 [ x+4]
take x2 common factor from first praket
x2[x+4] -9 [x+4]
= [x+4] *[x2 -9]
so the zeros of this equation are -4 , 3, -3

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