GhostElite8240 GhostElite8240

23-10-2017
Mathematics

contestada

If arrivals occur at a mean rate of 3.6 events per hour, the exponential probability of waiting more than 0.5 hour for the next arrival is:

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01-11-2017

The answer is 0.8347. Mean u = 1/m = 3.6 per hour Time x = 0.5 hour Exponential Probability = P(X <= x) Going by the Cumulative distribution function P(X <= x) = 1 - e^(-mx) P(X < .5) = 1 â€“ exp^(-3.6 x 0.5) = 1 â€“ 0.1653 = 0.8347

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