Getthere airlines currently charges $200$ dollars per ticket and sells $40{,}000$ tickets a week. for every $10$ dollars they increase the ticket price, they sell $1000$ fewer tickets a week. how many dollars should they charge to maximize their total revenue?

Question

amwatkins8104 amwatkins8104

24-11-2017
Business

contestada

Getthere airlines currently charges $200$ dollars per ticket and sells $40{,}000$ tickets a week. for every $10$ dollars they increase the ticket price, they sell $1000$ fewer tickets a week. how many dollars should they charge to maximize their total revenue?

Respuesta :

Otras preguntas

Find the prime factorization of 15

I am a triangle with one obtuse angle. Draw me.

A must decode this code. I guess is not a Cesar. The last line is a email adress.Please tell me a answer and how to decode...UG93aWVkeiBuYW0gdyBjenltIGplc3RlxZs

For what value of x is the rational expression below undefined?(3x-12)/(9-x)

which of the following word is applied to people who live on very little money, but who are NOT victims of abject poverty? A: penury B: indigence C: destitutio

Graph the points and state whether they are collinear. 1) (0,0), (4,2), (6,3) 2) (-1,1), (2,-2), (4,-3) 3) (-2,0), (0,4), (2,0) 4) (0,0), (6,0), (9,0) 5) (1,2

what does Eckles find on his boot at the end of the story a sound of thunder

Which group of algae is responsible for the formation of kelp beds along the north american coast?

Simplify. (2x∧3y5)∧4

Under the English Westminster model, the highest court of appeals is

bhootsath bhootsath · Answer 1 · 2017-12-03T17:51:17+01:00

Suppose GetThere Airlines increases their ticket price to $200+10n = 10(20+n)$ dollars. Then the number of tickets they sell is $40,000-1000n = 1000(40-n)$ . Therefore, their total revenue is

$10(20+n)\cdot 1000(40-n) = 10000(20+n)(40-n) = 10000(800+20n-n^2).$

This is maximized when $n=-\left(\frac{20}{2\cdot(-1)}\right)=10$ . Therefore, they should charge $200+10\cdot 10 = \boxed{300}$ dollars per ticket.