Franklyn6019 Franklyn6019
  • 24-03-2018
  • Physics
contestada

If the frequency of standing waves is 485 hz , how far apart are two adjacent nodes?

Respuesta :

skyluke89
skyluke89 skyluke89
  • 03-04-2018
Missing part in the text:
"The velocity of the standing wave is 95.0 m/s"

Solution:
first, we can find the wavelength of the wave, using the relationship between velocity, frequency and wavelength:
[tex]\lambda= \frac{v}{f} = \frac{95.0 m/s}{485 Hz}=0.196 m [/tex]

Then, we know that the distance between two adjacent nodes of a standing wave is equal to half the wavelength, so their distance is:
[tex]d= \frac{\lambda}{2}= \frac{0.196 m}{2}=0.098 m [/tex]

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