jetblackcap
jetblackcap
23-04-2018
Mathematics
contestada
Please help meeeeeee
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Аноним
Аноним
23-04-2018
(by + 2)/3 = c
by + 2 = 3c
by = 3c - 2
y = (3c - 2)/b
[tex]y = \frac{3c - 2}{b} [/tex]
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